Question

The age of father 8years ago was 5 times that of his son 8 years hence his age will be 8 years more than twice the age of his son. Find present age of father and son?

Answer 1

Step-by-step explanation:

Suppose present age of father is x and present age of son is y .

-- 8 years ago

Age of father = x - 8

Age of son = y - 8

-- Age of father was 5 times of his son

i.e. x - 8 = 5(y - 8)

x - 8 = 5y - 40

x - 5y = -32 ---------(1)

-- 8 years hence

Age of father = x + 8

Age of son = y + 8

--- Age of father will be 8 years more than twice the age of his son

i.e. x + 8 = 2(y + 8) + 8

x + 8 = 2y + 16 + 8

x + 8 = 2y + 24

x - 2y = 16 -----------(2)

Applying Elimination method

x - 5y = -32

x - 2y = 16

-. +. -

------------------

-3y = -48

3y = 48

y = 16

Applying y=16 in eqn (2)

x - 2(16) = 16

x - 32 =16

x = 16+ 32

x = 48

Therefore the present age of father is 48 years and present age of son is 16 years

Answer 2

✍︎.... ฅ^•ﻌ•^ฅ Aɴsᴡᴇʀ

Let age of father be x

And age of son be y

After four years

Age of father will be x+4

Age of son will be y+4

According to the question

x+4 = 3(y+4) - 8

⇒ x+4 = 3y + 12 - 8

⇒ x+4 = 3y + 4

⇒ x+4 - 4 = 3y

⇒ x = 3y

Given that son`s age = 10 yrs

⇒ y = 10

Father`s age = x = 3y 

⇒ x = 3 ×10

∴ x = 30

∴ Age of father = 30 years

❣︎ Hᴏᴘᴇ Iᴛ Hᴇʟᴘs ❣︎

#PsʏᴄʜᴏHᴇʀᴇ

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