Question

The age of father 8yrs back was 5 times that of his son.After 8yrs his age will be 8 y more than double the age of his son.Find their present ages.​

Answer 1

Answer:

let the age of son is x

and father's age is y

according to the question ,

8 year back,

y = 5 x -----(1)

present age of father is

y +8 = 5x + 8

and after 8 year

y = 2x +8

put value of y in equation (1)

2x + 8 = 5x

Now find the value of x and then

put value of x in equation (1) for find value of y