Question

the age of father and his son is in the ratio of 4:1. The sum of their ages is 60. Find their ages two year's ago
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Answer 1

Answer:

48 and 12

Step-by-step explanation:

age of father =x

age of son = y

x+y=60

x/y = 4/1 means x=4y

4y +y =60

5y =60

y=12

Answer 2

In context to question asked,

We have to determine the age of father and son which was two year's ago.

As per question,

It is given that,

The age of father and his son is in the ratio of 4:1.

As the sum of present age of father and son is 60 years.

So, let the age of father and son are 4x and x respectively.

So from above,

We will get,

$4x+x=60\\=>5x = 60\\=>x = \frac{60}{5} = 12\: years$

Hence, present age of father will be $=4x = (4\times 12) = 48\:years$

Present age of Son will be $=x = (1 \times 10) = 12\:years$

Hence, age of father 2 years before will be $=(48-2) = 46\:years$

Age of son 2 years before will be $=(12-2) = 10\:years$