Math, asked by nidhirathore574, 7 months ago

The age of father is 10 years more than twice the age of the son.​

Answers

Answered by dk4604905
0

Answer:

age of father ={2× age of son}+10

Step-by-step explanation:

age of father={2× 5}+10

Answered by BrainlyElegent
31

Solution:

Let , the son's present age be x yrs.

Now , A/Q ,

Present age of father = ( 3x + 3 ) yrs.

= (3x + 3 + 3 )

= 2(x + 3 ) + 10

= 3x + 6 = 2x + 16

.

. . x= 10

Again,

Father's present age = ( 3x + 3 )

= {(3×10)+3} yrs.

=33 yrs.

Therefore, father's present age is 33 years .

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