The age of father is 11 years less than twice the sum of the ages of his three children after 10 years he will be 5 years less than the sum of his children ages at that time find the age of the father
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Let the age of father be x and the ages of the son be a,b,c
We have been given
x=2(a+b+c)-11 and
after 10 years we have
x+10=(a+b+c+30)-5 why 10 and 30 as the age will increase
On solving the two equations we will get
a+b+c=26 so the age of father 41
We have been given
x=2(a+b+c)-11 and
after 10 years we have
x+10=(a+b+c+30)-5 why 10 and 30 as the age will increase
On solving the two equations we will get
a+b+c=26 so the age of father 41
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