The age of father is 13xy-6x²+4a-1.The age of the son is 25x²+16xy-3b²-2find the difference of ages
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Answer:
2+4a+3b²-22x²-3xy
Step-by-step explanation:
Age of father - Age of the son
= 13xy-6x²+4a-1-(25x²+16xy-3b²-2)
= 13xy-6x²+4a-1-25x²-16xy+3b²+2
= (-3xy-22x²+4a+3b²+2)
= 2+4a+3b²-3xy-22x²
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