The age of father is 20 years more than twice the age of son.If sum of their ages is 65 years, find the age of the father and son
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Let the age of son be ( x )
So, age of father will be ( 2x + 20 )
Sum of their ages = 65
=> x + 2x + 20 = 65
=> 3x = 45
=> x = 15
Hence, age of son = 15 years
Age of father = 2(15) + 20 = 50 years
So, age of father will be ( 2x + 20 )
Sum of their ages = 65
=> x + 2x + 20 = 65
=> 3x = 45
=> x = 15
Hence, age of son = 15 years
Age of father = 2(15) + 20 = 50 years
vedha03:
u should not take x = 2x+20 because age of son is not equal to the age of father so you should take x = 2y+20
ur answer is wrong
Dear
Please check your answer
Mine is correct
Ohh sorry it's my mistake
Ok
Answered by
4
hiii!!!
here's ur answer...
ATQ, the age of father is 20 yrs more than twice the age of his son.
let the age of son be x
therefore the age of father is 2x + 20
sum of their ages is given = 65 yrs
==> x + 2x + 20 = 65 yrs
==> 3x + 20 = 65 yrs
==> 3x = 65 - 20
==> 3x = 45
==> x = 45/3
==> x = 15
hence, age of son = x = 15 yrs
age of his father = 2x + 20 = ( 2 × 15 ) + 20 = 30 + 20 = 50 yrs
hope this helps...!!!
here's ur answer...
ATQ, the age of father is 20 yrs more than twice the age of his son.
let the age of son be x
therefore the age of father is 2x + 20
sum of their ages is given = 65 yrs
==> x + 2x + 20 = 65 yrs
==> 3x + 20 = 65 yrs
==> 3x = 65 - 20
==> 3x = 45
==> x = 45/3
==> x = 15
hence, age of son = x = 15 yrs
age of his father = 2x + 20 = ( 2 × 15 ) + 20 = 30 + 20 = 50 yrs
hope this helps...!!!
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