Question

The age of father is 25 years more than the age of his son .Before 10 years father's age was two times of his son ,Find their present age

50 Points Question

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Answer 1

Step-by-step explanation:

Let the present age of Son = x years

then Father's present age = (x+25) years

Before 10 yrs ,

x + 15 = 2(x-10)

x + 15 = 2x - 20

x = 35

Son's age (x) = 35 years

& Father's age (x+25) = 60 years

So, the son's present age is 35 years & Father's present age is 60 years .

Answer 2

$\huge{\bf{\underline{\purple{Solution :}}}}$

• Supoose the age of father = x years
• So , the age of son = y years

Now According to Question  First  Case :

$:\implies \bold{\bf{x = y +25}}}$.......................1))Equation

Given that Before 10 years , their age will be :

• (x - 10) and (y -10)

According to Question Second Case :

$\implies \bold{(x -10) = 2(y -10)}}$

$\implies \bold{x - 10 = 2y -20}}$

$\implies \bold{x = 2y - 20 +10}}$

$\implies \bold{x = 2y - 10}}$...........................2)) Equation

Now Put the value of x in equation First :

$\longrightarrow \bold{y + 25 = 2y - 10}}$

$\longrightarrow \bold{25 + 10 = 2y - y }}$

y = 35

Put the value of y in equation 1) :

∴ x = 35 + 25 = 60

Father age - 60 years

Son age - 35 years

$\rule{200}2$