Question

The age of father is 28yrs more than the age of his son after 8yrs the age of father will be twice the age of his son find their present ages

Answer 1

let the present age of son = x yrs

[then the present age of father = (x+28)

after 8 yrs

(x + 36) = 2(x + 8)

[x + 36 = 2x + 16

x = 20 years

so the present age of son = 20 years

and the present age of father = 48 yrs