The age of father is 3 times the sum of ages of his 2 children. After 5 years his age will be equal to the twice the
sum of ages of his children. Find the age of the father.
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age of 2 children=x+y
age of father= 3(x+y)
after 5 years 2 children age=((x+5)+(y+5))=(x+y+10)
after 5 years father age=2(x+y+10)
then 3(x+y)+5=2(x+y+10)
x+y=15
present age of father= 2(x+y+10)=50
age of father= 3(x+y)
after 5 years 2 children age=((x+5)+(y+5))=(x+y+10)
after 5 years father age=2(x+y+10)
then 3(x+y)+5=2(x+y+10)
x+y=15
present age of father= 2(x+y+10)=50
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