Math, asked by annapoornasystems, 1 year ago

the age of father is 3 years more than 3 times the son's age. 3 years after the age of the father will be 10 years more than twice the age of his son. find their present ages.

Answers

Answered by saubia
1
 let the age of son be x so the age of father will be 3x+3
3 yrs after the age of son and father will be x+3 and 3x+6 respectively
by the given condition
3x+6=2(x+5)+10
3x+6=2x+20
x=14
therefore present ages of son and his father is 14 and 45
Answered by yogish2k
1
4x+5=3 (x+5)
4x+5=3x+15
4x-3x=15-5
×=10
Age of the father =4x=4 (10)=40
Age of the son =x=10
After 5 years age of the father=40+5=45
Age of the son=10+5=15
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