Question

The age of father is 3 years more than three times the son 's age. 3 years hence the age of father will be 10 years more than twice the age of the son. find their present ages?

Answer 1

let son's age be= s
.'. father age = t
t= 3s+3   ------ (1)
3 years hence the son's age will be= s+3
.'. father age = 2s + 13
.'. son's age =  3s+3 = 2s+13
⇒3s-2s=13 -3                     
⇒s=10
.'. son's age = 10
& fathers age = 10 * 3 + 3= 33