The age of father is 30 years more than that of his son. 5 years hence father’s age willbe thrice of his son’s age, find their present ages.
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Let the age of the father and his son be " a and b " respectively
By the conditions given in the question we get equations
a = b + 30
a - b = 30. .... 1
a + 5 = 3 ( b + 5 )
a - 3b = 10. .... 2
Subtracting equation 2 from equation 1 we get
2b = 20
b = 10
putting ( b = 10 ) in equation 1
a - 10 = 30
a = 40
so the present ahes of the father and his son are 40 and 10 years respectively
By the conditions given in the question we get equations
a = b + 30
a - b = 30. .... 1
a + 5 = 3 ( b + 5 )
a - 3b = 10. .... 2
Subtracting equation 2 from equation 1 we get
2b = 20
b = 10
putting ( b = 10 ) in equation 1
a - 10 = 30
a = 40
so the present ahes of the father and his son are 40 and 10 years respectively
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Answer:
The age of father is 30 years more than that of his son 5 years hence ... son 5 years hence father's age will be three of his son's age find their present age. 2 ... After 5 years, father will be three times the age of his son = 3{x + 5).
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