the age of father is 30 years more than that of his son 5 years hence father's age will be three of his son's age find their present age
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Answered by
64
Answer:
Present age of son = 10 years
Present age of father = 40 years
Step-by-step explanation:
Step 1 : Define x
Let the present age be x years
Given, father is 30 years old than his son
So let the age of father be x + 30
After 5 years, age of son = x + 5 and age of father = x + 30 + 5 = x + 35
After 5 years, father will be three times the age of his son = 3{x + 5)
Step 2 : Find the value of x
3(x + 5) = x + 35
=> 3x + 15 = x + 35
=> 3x - x = 35 - 15
=> 2x = 20
=> x = 10
Step 3 : Find their present ages
Present age of son => x years
=> 10 years
Present age of father = x + 30
=> 10 + 30
=> 40 years
lavikumar:
why
Answered by
45
here is your answer OK ☺☺☺☺☺☺☺☺
suppose the present age of of father is x
so given question in 30 year more so (X +30)
after five year age of son (x+5)and father (x+35)
given in this question after father will be thrice of son so... 3(x+5)
so equation....
3(x+5)=x+35
3x +15 = X +35
3x-x= 35 - 15
2x = 20
X = 20/2
x= 10
present age of son = 10
so father age = X + 30 = 10 + 30 = 40
thanks for asking this question ☺☺
suppose the present age of of father is x
so given question in 30 year more so (X +30)
after five year age of son (x+5)and father (x+35)
given in this question after father will be thrice of son so... 3(x+5)
so equation....
3(x+5)=x+35
3x +15 = X +35
3x-x= 35 - 15
2x = 20
X = 20/2
x= 10
present age of son = 10
so father age = X + 30 = 10 + 30 = 40
thanks for asking this question ☺☺
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