Question

The age of father is 4 times the age of his son.5 years ago the father was 7 times the age of his son.Find their present ages​

Answer 1

Let the age of the son = x

Let the age of the son = xThen the age of the father = 4x

5 years ago:

Age of the son = x - 5

Age of the father = 7 (x - 5)

Present ages:

7 (x - 5) = - (y - 5)

7x - 35 = 4x - 5

7x - 4x = 35 - 5

3x = 30

x = 10

Therefore:

The age of the son = x = 10 years

The age of the father = 4x = 40 years