the age of father is 40 years more than that of his son after 5 years father age will be twice his son find their present ages
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Answered by
3
let the father's age be x
the son's age be y
ATQ, x=40y
case II: 5x = 2y
this is the equation plz try urself
the son's age be y
ATQ, x=40y
case II: 5x = 2y
this is the equation plz try urself
adityabjadhaogmail:
thanks
Answered by
9
✒✒Let the present age of son = x years
The present age of father = x + 40 years
After 5 years,
Age of son = x +5 years
Age of father = x + 45 years
A.T.Q
3(x + 5) = x + 45
3x + 15 = x + 45
3x - x = 45 - 15
2x = 30
x = 30
2
x = 15
If x = 15 , x + 40 = 55✔✔
Hence present age of son is 15 years and father is 55 years.✔✔
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