Math, asked by adityabjadhaogmail, 1 year ago

the age of father is 40 years more than that of his son after 5 years father age will be twice his son find their present ages

Answers

Answered by monisha340417
3
let the father's age be x
the son's age be y
ATQ, x=40y
case II: 5x = 2y
this is the equation plz try urself

adityabjadhaogmail: thanks
Answered by anishka56
9

\huge\blue{ANSWER}

✒✒Let the present age of son = x years

The present age of father = x + 40 years

After 5 years,

Age of son = x +5 years

Age of father = x + 45 years

A.T.Q

3(x + 5) = x + 45

3x + 15 = x + 45

3x - x = 45 - 15

2x = 30

x = 30

2

x = 15

If x = 15 , x + 40 = 55

Hence present age of son is 15 years and father is 55 years.

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