Question

the age of father is 40 years more than that of his son after 5 years father's age will be thrice his son's age . find their present ages.

Answer 1

Answer:

The father is 55 years old and his son is 15 years old

Step-by-step explanation:

f = s + 40

f + 5 = 3 (s + 5)

(s + 40) + 5 = 3 (s + 5)

s + 45 = 3s + 15

-2s = -30

s = 15

f = s + 40

f = 15 + 40

f = 55

f = s + 40

f + 5 = 3 (s + 5)

(s + 40) + 5 = 3 (s + 5)

s + 45 = 3s + 15

-2s = -30

s = 15

f = s + 40

f = 15 + 40

f = 55

The father is 55 years old and his son is 15 years old

Answer 2

son age be x
father age x + 40

after 5 years sons age x +5
after 5 years farter age x + 40 +5

3(x +5) = X + 40 + 5
3x + 15 = x + 45

3x _ x = 45 - 15
2x = 30
x = 30/2
x = 15

son age = 15 years
father age = 15+40 =55years