Business Studies, asked by pranshurana62, 1 year ago

The age of father is 5 times that of his son 3 years agothe age of father was 8 times that of his son.Find the present age of father hints a)42 b)48 c)40 d)35

Answers

Answered by Smartyyogi45
6
let, present age of son = x
then, present age of father = 5x
3 Years ago
Age of son = x-3
Age of Father = 5x-3
=>
5x - 3 = 8 \times (x - 3)
=>
5x-3 = 8x - 24
=>
-3+24=8x-5x
=>
21=3x
x =7
so present age of son = 7 yrs.
and present age of father = 35 yrs.

So The correct option is (d) 35
Answered by Anonymous
1
let present age of Son be x and of father's be 5x.
8(x-3)=(5x-3)
8x-24=5x-3
3x=21
x=7
then father's age will be 5x =5(7)=35 yrs.
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