Math, asked by kaju1434, 2 months ago

The age of father is 5 years more than twice the age of son​

Answers

Answered by Anonymous
0

Answer:

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Step-by-step explanation:

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A father is 5 years more than twice as old as his son. The difference in their ages is 25 years. How old is the father?

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Let the age of son is x years

Age of father = 2x+5 years

Difference in their ages is 25 years, i.e.

(2x+5) - x = 25 years

x = 20 years (Son's age)

The age of father = 2x+5 = 2×20+5 = 45 years

Answered by radhikarustagi
0

Answer:

2s+5

son = s

twice = ×2

5 years = +5

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