The age of father is 5 years more than twice the age of son
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Step-by-step explanation:
A father is 5 years more than twice as old as his son. The difference in their ages is 25 years. How old is the father?
Let the age of son is x years
Age of father = 2x+5 years
Difference in their ages is 25 years, i.e.
(2x+5) - x = 25 years
x = 20 years (Son's age)
The age of father = 2x+5 = 2×20+5 = 45 years
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Answer:
2s+5
son = s
twice = ×2
5 years = +5
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