The age of father is four times the age of the son and
the sum of their ages is 40 years Represent this
situation in the form of linear equations in 2
variables algebraically.
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Let son age = x
Fathers age = 4 x
Sum of their age = 40
A.T.Q
x + 4 x = 40
5 x = 40
x = 40 / 5
x = 8
Son Age = 8
Fathers Age = 4 × 8
= 32
Answered by
0
Answer:
Let the age of son be x
Father's age be 4x
x+4x =40
5x=40
x=40\5
x=8
age of son =x=8 years
age of father=4x=32 years
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