Question

The age of father is three times the age of his son. Five years ago, the father was four times son's age at that time.

Represent the above statement by two linear equations in two variables.

Guys! Please help me out!!​

Answer 1

Answer:

et the father present age =x years  and son present age =y years

According to the first condition

5 years later father will be (x+5) years old and son will be (y+5) years old.

⇒x+5=3(y+5)

⇒x+5=3y+15⇒x=3y+10....eq1

According to the second condition

5 years ago father was (x−5) years old and son was (y−5) years old.

⇒x−5=7(y−5)

⇒x−5=7y−35

⇒x−7y=−30....eq2

Put  the value of x from eq1

⇒3y+10−7y=−30⇒−4y=−40⇒y=10

Put y=10 in eq1

⇒x=3×10+10=40

 

Hence, Father present age =40 years

Son present age =10 years

Step-by-step explanation:

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Answer 2

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