the age of father is three times the sum of ages of his two children after 5 years his age will be two times the sum of the ages of children.find the present age of father.
Answers
✬ Father's Age = 45 Years ✬
Step-by-step explanation:
Given:
- Father age is three times the sum of ages of his two children.
- 5 years later father's age will be two times the sum of ages of his children.
To Find:
- What is the present age of father ?
Solution: Let the ages of his two children be x and y. Therefore,
➟ Present age of father = 3(sum of x + y)
➟ Present age of father = 3(x + y)....(1)
[ Now, after 5 years their ages will be ]
- 1st children age = (x + 5) years
- 2nd children age = (y + 5) years
- Father's age = 3(x +y) + 5 years
A/q
- 5 years later father's age will be two times the sum of ages of his children.
3(x + y) + 5 = 2(x + 5 + y + 5)
3x + 3y + 5 = 2(10 + x + y)
3x + 3y + 5 = 20 + 2x + 2y
3x – 2x + 3y – 2y = 20 – 5
x + y = 15.....(1)
So, present age of father is
➙ 3(x + y)
➙ 3(15) { from equation 1 }
➙ 45 years
Hence, Present age of father is 45 years.
Step-by-step explanation:
- The age of father is three times the sum of ages of his two children.
- After 5 years his age will be two times the sum of the ages of children.
- The present age of father.
Let the age of father be x
And sum of ages of his two children be y
According to the 1st condition:-
The age of father is three times the sum of ages of his two children.
So:-
According to 2nd condition:-
After 5 years his age will be two times the sum of the ages of children.
After 5 years
Age of father = (x + 5)
Sum of ages of his two children = y + 10
He will be two twice the sum of ages of his children.
Substituting equation (i) in (ii)
Substituting y = 15 in equation (ii)