Question

The
age of father is three years
more than three times the age of
his son. Three years hence, the
father's
age will be ten years more
than twice the
age of
the son
Determine their
ages.
present​

Answer 1

Let father’s age be x & son’s age be y

By 1st condition:

3 + 3y = x (three plus three times age of son is father’s age)

By 2nd condition:

x + 3 = 2(y + 3) + 10 [here we are talking about 3 years hence. So 3 has to be added to their present ages, and then satisfy the condition]

So the final 2 equations are

x-3y = 3 … (1)

x-2y = 13 … (2)

Solving them we get

y = 10, x = 33

So the father’s present age is 33 and that of the son is 10.