Question

the age of father is twice the sum of the ages of his two children .after two years his age will be equal to the sum of the ages of his children. find the age of the father .​

Answer 1

Answer:

40 years

Step-by-step explanation:

Okay so there is a correction in your question. The correct question is :-

The age of father is twice the sum of the ages of his two children. After twenty years his age will be equal to the sum of the ages of his children. Find the age of the father.

Reason for correction?

If we we'll take it as two years then father's age will come out to be 4 years! And by no means 4 year boy can be assumed a father xD xD

Now, Solution :

Let the age of father be x years

Let the age of one of his children be y years and age of other children be z years

From given information we can infer,

x=2×(y+z) ......(1)

After 20 years,

(x+20)=(y+20)+(z+20)  .......(2)

Now, on substituting value of (1) in (2), we get

2×(y+z) +20=y+z+40

2y+2z−y−z=40−20

y+z=20    ......(3)

Now, Substituting value of (3) in (1), we get

x=2×(20)

⇒x=40

Hence, Age of the father is 40 years.

Answer 2

AnswEr:-

Present age of father = 40 years.

$\rule{200}{1}$

Correct question:-

The present age if father is twice the sum of the ages of two children. After 20 years, his age will be equal to the sum of the ages of his two children.Find the present age of father.

Given:-

• Father's age = 2 × (sum of ages of two children)
• After 20 years,father's age = Sum of ages of two children.

To find:-

• Present age of father = ?

Solution:-

Let the present age father be a years and the present ages of two children be b & c year respectively.

According to question:-

↠ a = 2(b + c) ----(eq.1)

2nd case:-

↠ (a + 20) = (b + 20 + c + 20)

• Putting value from (eq.1)

↠2( b + c) + 20 = b + c + 40

↠ 2b + 2c + 20 = b + c + 40

↠ 2b - b + 2c - c = 40 - 20

↠ b + c = 20

∴ Sum of ages of children = 20 years.

• Putting value in (eq.1):-

↠ a = 2(20)

↠ a = 40

∴ Present age of father = 40 years.