Math, asked by sonikagurung0707, 7 hours ago

The age of father to that of his son is in the ratio 4:1.Five years ago,the ratio of their ages was 7:1.Find their present ages.​

Answers

Answered by prabhanidhi2
1

Answer:

let the present age of father and son be 4x and 1x

five years ago

age of father = 4x - 5

age of son = 1×-5

:- 4x -5/1×-5 =7/1

:- 1(4×-5)=7(1×-5)

:- 4x-5=7×-35

:- 3x = 30

x = 10

hence age of :-

father = 40 years

son = 10 years

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