the age of John's father is three times the age of John five years ago, the age of the father was four-time John's age that time. find their present ages
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Answer:
John’s Father = F
John = J
sister Alice = A
F = 5*J
J = 2*A
In two years the sum of their ages (everyone’s age + 2):
(F+2) + (J + 2) + (A + 2) = 58
we get three equations:
F = 5*J
J = 2*A
F + J + A + 6 = 58
We rewrite J = 2*A as A = J/2
F = 5*J
A = J/2
F + J + A = 58 - 6
We apply F and A values in latest equation:
5*J + J + J/2 = 52
sum
6.5*J = 52
J = 8
Therefore John’s Ages is: 8 years
(Father’s = 8*5 = 40)
(Sister = 8/2 = 4)
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