Question

the age of leena and heena are in the ratio 7/5 ten year hence the ratio of their ages will be 9/7 find their present ages

Answer 1

let present age of leena is X years
present age of Heena is y years
X/y=7/5
X=7/5y
after 10 years age of leena is X+10 and age of Heena is y+10
X+10/y+10=9/7
7x+70=9y+90
7×7/5y=9y+20
49/5y-9y=20
4y=100
y=25
X=7/5×25=35

Answer 2

Answer:

The Present ages are -

• Leena = 35 years
• Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years