Math, asked by somen69, 1 year ago

The age of Leena and Heena are in the ratio 7:5 . Ten years hence the ratio of their ages will be 9:7 . Find their present ages.

Answers

Answered by brijeshkumar8084
1
Let the present age of Leena and heena be 7x and 5x
Ten years hence
Age of Leena=7x+10
Age of heena=5x+10
Then,
7x+10/5x+10=9/7
49x+70=45x+90
49x-45x=90-70
4x=20
x=5

ans(-Present age of Leena =7*5=35
Present age of Heena=5*5=25
Answered by viny6
2

hey mate

here is your answer

Let the ages of Leena and Heena be 7X and 5X

10 yrs later, they would be 7X +10 and 5X + 10 years old.

According to question, 7X+10/5X +10 = 9/7

===> 49X + 70 = 45X + 90 ===> 4X = 20 ===> X =5

Therefore Leena’s age is 35 while heena 25

hope it's helps

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viny6: please mark me as brainliest
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