The age of Leena and Heena are in the ratio 7:5 . Ten years hence the ratio of their ages will be 9:7 . Find their present ages.
Answers
Answered by
1
Let the present age of Leena and heena be 7x and 5x
Ten years hence
Age of Leena=7x+10
Age of heena=5x+10
Then,
7x+10/5x+10=9/7
49x+70=45x+90
49x-45x=90-70
4x=20
x=5
ans(-Present age of Leena =7*5=35
Present age of Heena=5*5=25
Ten years hence
Age of Leena=7x+10
Age of heena=5x+10
Then,
7x+10/5x+10=9/7
49x+70=45x+90
49x-45x=90-70
4x=20
x=5
ans(-Present age of Leena =7*5=35
Present age of Heena=5*5=25
Answered by
2
hey mate
here is your answer
Let the ages of Leena and Heena be 7X and 5X
10 yrs later, they would be 7X +10 and 5X + 10 years old.
According to question, 7X+10/5X +10 = 9/7
===> 49X + 70 = 45X + 90 ===> 4X = 20 ===> X =5
Therefore Leena’s age is 35 while heena 25
hope it's helps
please mark me as brainliest
viny6:
please mark me as brainliest
Similar questions