Math, asked by bandanapradhan1984, 8 months ago

the age of Leena and Heena are in the ratio 7 by 5 10 years hence the ratio of their ages will be 39 by 7 find their present ages​

Answers

Answered by zakshiva
0

Answer:

The ages of Leena and Heena are in the ratio 7:5. Ten years hence, the ratio of their ages will be 9:7. The ages of Leena and Heena are in the ratio 7:5. Ten years hence, the ratio of their ages will be 9:7.

Step-by-step explanation:

let Leena's present age be 7x years and Heena's present age be 5x years            

 After 10 years,

Leena's age=7x+10

Heena's age=5x+10

7x+10+5x+10=9x+7x

20=16x-12x

20=4x

x=5

Leena's present age=7x=7×5=35

Heena's present age=5×5=25

Answered by anadikedia4
19

Answer:

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