Math, asked by jatinrai1309, 1 year ago

The age of Leena and Heena in ratio is 7:5 . Ten years hence the ratio of their age will 9:7 . Find their present age

Answers

Answered by manu233
2
80% is the answer of Question
Answered by Sauron
8

Answer:

The Present ages are -

  • Leena = 35 years
  • Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

  • Leena as 7x
  • Heena as 5x

\rule{300}{1.5}

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

\rule{300}{1.5}

Heena's age =

➡ 5 × 5

➡ 25

\rule{300}{1.5}

Leena's age =

➡ 7 × 5

➡ 35

\therefore The Present ages are -

  • Leena = 35 years
  • Heena = 25 years
Similar questions