Question

the age of Leena and meena are in the ratio 7:5 ten years hense, the ratio of their ages will be 9:7 . Find their present ages .

Answer 1

let present age of leena and meena be 7x and 5x respectively.

A/q
7x+10/5x+10=9/7

7(7x+10)=9(5x+10)

49x+70=45x+90

49x-45x=90-70

4x=20

x=20/4=5

so,present age of leena=5×7=35years

and present age of meena=5×5=25years

Answer 2

Answer:

The Present ages are -

• Leena = 35 years
• Heena = 25 years

Step-by-step explanation:

Given :

Ages of Leena and Heena are in Ratio = 7 : 5

Ratio after 10 Years = 9 : 7

To Find :

Their present Ages

Solution :

Let the present Ages be -

• Leena as 7x
• Heena as 5x

$\rule{300}{1.5}$

➡ (7x + 10)/(5x + 10) = 9/7

➡ 7(7x + 10) = 9(5x + 10)

➡ 49x + 70 = 45x + 90

➡ 49x - 45x = 90 - 70

➡ 4x = 20

➡ x = 20/4

➡ x = 5

$\rule{300}{1.5}$

Heena's age =

➡ 5 × 5

➡ 25

$\rule{300}{1.5}$

Leena's age =

➡ 7 × 5

➡ 35

$\therefore$ The Present ages are -

• Leena = 35 years
• Heena = 25 years