Question

The age of madhu is thrice the age of her daughter.ten years ago the ratio of daughter age to that of madhu was 1:7 find the present age

Answer 1

Let the age of Madhu's daughter be x years

Madhu is thrice the age of her daughter

So, let the age of Madhu be 3x years

Ten years ago, age of Madhu's daughter = x - 10 and age of Madhu be 3x - 10

Ten years ago, the ratio of their ages was 1 : 7


According to the question,

$\dfrac{x - 10}{3x - 10} =\dfrac{1}{7}$

➾ $7(x\:-\:10)\:=1(3x\:-\:10)$

➾ $7x\:-\:70\:=\:3x\:-\:10$

➾ $7x\:-\:3x\:=\:70\:-\:10$

➾ $4x\:=\:60$

➾ $x\:=\:15$



∴ Present age of Madhu's daughter ➾ x years

➾ $\green{\boxed{\green{\boxed{\red{\textsf{15\:years}}}}}}$


∴ Present age of Madhu ➾ 3x years

➾ 3 × 15

➾ $\green{\boxed{\green{\boxed{\red{\textsf{45\:years}}}}}}$

Answer 2

$<b><u>BACKKK TO BACKKK!!!!!!$


==>> hey,,,

given= ,,

let's madhu's age be 'x'...

ten years ago!!!!!!!

since she is thrice her daughter,,,, it is given by..

3x -10 = x - 10..

given,,, ratio of madhu's age to her daughter's age is 1:7..

then,,,

x -10/ 3x-10= 1/7

7(x - 10)= 3x - 10..

7x -70 = 3x - 10

4x = 60..

x = 15 years...

but according to situation,,,

madhu's age is 3x,,,

i.e, 3(15)= 45...

and her daughter's age,, is 15 years...

and ten year's ago,,,

her daughter's age and her age were,, 5 years and 35 years...

$<b><u>Rgrds....@stylg..$>>