Question

the age of mintu and chintu are in the ratio 7:6. four years later the sum of Their ages will be 56 years . what are their present ages?​

Answer 1

EXPLANATION.

Let the age of mintu be = 7x

Let the age of chintu be = 6x

Four years later,

Let the present age of mintu = ( 7x + 4 )

Let the present age of chintu = ( 6x + 4 )

Their age will be = 56.

=> ( 7x + 4 ) + ( 6x + 4 ) = 56

=> 7x + 4 + 6x + 4 = 56

=> 13x + 8 = 56

=> 13x = 48

=> x = 48/13.

Therefore,

Present age of mintu = 7x = 7 X 48/13 = 336/13

present age of chintu = 6x = 6 X 48/13 = 288/13

Answer 2

Given :-

• The age of mintu and chintu in the ratio = 7:6.

• Four year later, the sum of their ages will be 56 years.

To Find :-

• Mintu and chintu present age.

Solution :-

Let,

• Age of Mintu = 7x.

• Age of Chintu = 6x.

After Four year,

• Age of Mintu = (7x + 4).

• Age of Chintu = (6x + 4).

• Sum of there age = 56.

$: \implies\sf{(7 x + 4) + (6x + 4) = 56}$

Then, we will add

• 7 and 6

• 4 and 4

$: \implies\sf{13x + 8 = 56}$

Then, we will minus 56 and 8.

$: \implies\sf{13x = 48}$

$: \implies\sf{x = \dfrac{48}{13} }$

So,

• Age of Mintu = 7 × 48/13 = 336/13.

• Age of Chintu = 6 × 48/13 = 288/13.