Math, asked by Ranghanayagee, 8 months ago

the age of Mohanlal is three times that of his son. If the difference of their ages is 32 years . find the age of his son​

Answers

Answered by Anonymous
2

Answer:

Let the age of Mohanlal's son be x years.

Mohanlal's age = 3 times his son's age

                           = 3x

Difference of their ages = 32 years

therefore, 3x - x = 32

               = 2x = 32

               = x = 32/2

              = x = 16

Therefore, his son's age = x = 16 years

Hope this helped you.

Answered by pandaXop
9

Son = 16 years

Mohanlal = 48 years

Step-by-step explanation:

Given:

  • Age of Mohanlal is three times of his son.
  • Difference between their ages is 32 years.

To Find:

  • What is the present age of his son ?

Solution: Let the age of his son be x years. Therefore,

Age of Mohanlal = 3 times of his son's age

Mohanlal's age = 3x years.

[ Difference between their ages ]

(Mohanlal's – Son's) age = 32 years

A/q

\implies{\rm } 3x x = 32

\implies{\rm } 2x = 32

\implies{\rm } x = 32/2

\implies{\rm } x = 16

So

• Age of Mohanlal is x = 16 years

• Age of his son is 3x = 3(16) = 48 years

[ Verification ]

➯ (Mohanlal's – Son's) age = 32 years

➯ (48 – 16) = 32

➯ 32 = 32

\large\bold{\texttt {Verified }}

Similar questions