Question

the age of monu is one-third the age of his mother. If the sum of their ages is 48years, find the age of both.​

Answer 1

Let the age of Monu's mother be 'x'
This implies age of Monu is 1/3 of x which is ( x/3 )
Given that,
Sum of their ages is 48 years.
Therefore
⇒ x + x/3 = 48
Taking LCM we get,
⇒ ( 3x + x )/3 = 48
⇒ 4x/3 = 48
⇒ 4x = 48 × 3
⇒ 4x = 144
⇒ x = 144/4
⇒ x = 36
Therefore the age of Monu's mother is 36 years.
Age of Monu = x/3
⇒ Age of Monu = ( 36/3 )
⇒ Age of Monu = 12 years
Therefore age of Monu is 12 years

Answer 2

Answer:

Age of Monu mother = 36 years

Age of Monu = 12 years

Step-by-step explanation:

Let the age of the mother be X years

Age of Monu = 1/3x years

given X+1/3x = 48

X(1+1/3) = 48

4/3x = 48

4x = 144

X = 144/4

= 36

Hence the age of Monu mother = 36 years

Age of Monu = 36/3 = 12 years