Question

the age of monu is one third the age of his mother if the sum of their age is 48 years find the age of both

Answer 1

hello

let the age of monu mother be x and monu be 1/3 x

A/q to question

x +1/3x = 48

4x = 48×3

x = 48×3/4

x = 36

age of monu mother = 36 years

age of monu = 1/3 x = 1/3 ×36= 12 years

hope it helps :)

Answer 2

$\huge\sf{\underline{\underline{Solution:}}}$

• Let the age of Monu's mother be 'x'

• This implies age of Monu is 1/3 of x which is ( x/3 )

Given that,

• Sum of their ages is 48 years.

Therefore

⇒ x + x/3 = 48

Taking LCM we get,

⇒ ( 3x + x )/3 = 48

⇒ 4x/3 = 48

⇒ 4x = 48 × 3

⇒ 4x = 144

⇒ x = 144/4

⇒ x = 36

Therefore the age of Monu's mother is 36 years.

Age of Monu = x/3

⇒ Age of Monu = ( 36/3 )

⇒ Age of Monu = 12 years

Therefore age of Monu is 12 years