Question

The age of monu is one-third the age of his mother. If the sum of thier age is 48 years find the age of both.

Answer 1

monu= 1\3

=1/4

=48/4

=12

12-3

=9

=9into3

=27

monus age=9

mothers age =27

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Answer 2

$\huge\sf{Answer}$

• Let the age of Monu's mother be 'x'

• This implies age of Monu is 1/3 of x which is ( x/3 )

Given that,

Sum of their ages is 48 years.

Therefore

⇒ x + x/3 = 48

Taking LCM we get,

⇒ ( 3x + x )/3 = 48

⇒ 4x/3 = 48

⇒ 4x = 48 × 3

⇒ 4x = 144

⇒ x = 144/4

⇒ x = 36

Therefore the age of Monu's mother is 36 years.

Age of Monu = x/3

⇒ Age of Monu = ( 36/3 )

⇒ Age of Monu = 12 years

Therefore age of Monu is 12 years

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