Question

the age of rachita s father is 7/3 of rachita s ageand sum of their age is 50 years find their age​

Answer 1

Required Answer:

Given:

• The age of Rachita's father is 7/3 of Rachita's age.

• The sum of their age is 50 years.

To Find :

• Their age

Calculation:

Let the age of Rachita be x.

According to the question :

• Age of Rachita's father = $\tt { \dfrac{7}{3}x}$

• Sum of their age is 50 years.

$\tt { \implies \dfrac {7}{3} x + x=50}$

Solving this equation to find their ages-

$\large \tt { \qquad \dfrac {7}{3} x + x=50}$

$\:$

$\tt { \qquad \implies \dfrac{7x +3x}{3} =50}$

$\:$

$\tt { \qquad \implies \dfrac{10x}{3} =50}$

$\:$

$\tt { \qquad \implies 10x =50 \times 3}$

$\:$

$\tt { \qquad \implies 10x = 150}$

$\:$

$\tt { \qquad \implies x = \dfrac{150}{10} }$

$\:$

$\tt\red { \qquad \implies x = 15}$

Therefore,

• Age of Rachita = x = 15 years.

• Age of Rachita's father = $\tt { \dfrac{7}{3}x}$ = 35 years

$\tt { \leadsto \dfrac{7}{\cancel {3} } \times \cancel {15} }$

$\tt { 7 \times 5 =35years}$

_________________________________

Answer 2

$\large\blue{\mid{\fbox{\tt{AnsWer}}\mid}}$

As per the given statement, ratio of age of father to that of Rachita is 7 : 3. as $\sf\dfrac{7}{3}=7:3$

Let the rationale between the age of father to Rachita be x. As such the ages of father and Rachita will be 7x and 3x respectively.

Sum of their ages is 50 yr. As such

$⟾7x + 3x = 50$

$⟾10x = 50$

$⟾x =\dfrac{50}{10}$

$\fbox{⟾x = 5}$

The rationale is 6, therefore

Father's age is $7x = 7 × 5=35 years$

Rachita's age is $3x = 3 × 5 = 15 years$

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