Question

The age of Rahu and Ketu are in the ratio of 7 ratio 5 the 10 years hence the ratio of their ages will be 9 ratio 7 find their present age

Answer 1

Answer:

Let the number be x

and the two numbers are in the ratio of

first we add the number between numerator and denominator 7x/5x+10=9/7

9(5x+10)=7(7x+10)

45x+90=49x70

45x-49x=-90+70

-4x =-20

x=-20÷-4=5

Answer 2

Let the current ages of Rahu and Ketu be x and y respectively.

Ratio is 7:5 x:y is 7:5

x/y =7/5

5x=7y

5x-7y=0 --i

After 10 yrs

The ratio is 9:7

(x+10)/(y+10) =9/7

7x+70=9y +90

Solving the above equation.

7x-9y=20—ii

Solve eq-i &eq-ii on both side.

7x-9y=20

5x-7y=0

x=7y/5

substitute the value of X in eq-ii

7*7y/5–9y=20

49y-45y=100

4y=100

y=25

x =7*25/5 = 35

Rahu  is 35yrs

Ketu  is 25yrs