Math, asked by divyasoni7077, 5 months ago

The age of Rahul 's father is 4 times of his age . If the sum of there ages is 40 years , then the difference of there ages​

Answers

Answered by umeshbhatt2003
2

Answer:

A father is 4 times older than his son. In 20 years he will be twice as old as his son. What ages do they have now?

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f=4s

f+20=2(s+20)

4s+20=2s+40

4s=2s+20

2s=20

s=10,f=40 (son is 10, father is 40)

Let son's age is x years

father is 4 times older than his son hence father age will be 4x

In 20 years he will be twice as old as his son. After 20 years their ages will be

Son age = x + 20

Father's age = 4x + 20

4x + 20 = 2 ( x + 20 )

Solving the equation

4x + 20 = 2x + 40

4x - 2x = 40 - 20

2x = 20

x = 10

The son's present age is 10 years

Father's age is 4x= 4 × 10 = 40 years.

Answer son's present age 10 years and father's present age is 40 years

Let us check the correctness of answer by putting their respective ages in the equation.

4x + 20 = 2x + 40

4 × 10 + 20 = 2×10 + 40

40 + 20 = 20 + 40

60 = 60

Means answer is correct.

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Answered by smith2107
1

Answer:

24

Step-by-step explanation:

let the no. be X .

4x+x=40

5x=40

x=40/5

x= 8

So, Rahul age is 8 and his father age will be 4*8=32

difference is:

32-8=24

And=24

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