Math, asked by sivaprasadmp06, 6 months ago

The age of Rajan is 9 times that of his son. After 3 year age of Rajan would be 5 times then of his son. What are their age now?​

Answers

Answered by MяƖиνιѕιвʟє
27

Given :-

  • The age of Rajan is 9 times that of his son. After 3 year age of Rajan would be 5 times then of his son.

To find :-

  • Present age of Rajan and his son

Solution :-

Let the present age of Rajan's son be x then Rajan's present age be 9x

  • After 3 years
  • Rajan's son age = x + 3
  • Rajan's age = 9x + 3

After 3 year age of Rajan would be 5 times then of his son.

According to the given condition

→ 5(x + 3) = 9x + 3

→ 5x + 15 = 9x + 3

→ 15 - 3 = 9x - 5x

→ 12 = 4x

→ 4x = 12

→ x = 12/4

→ x = 3

Hence,

  • Present age of Rajan's son = x = 3 years
  • Present age of Rajan = 9x = 27 years
Answered by Anonymous
19

AnswEr :-

• Present ages of Rajan's son is 3 years.

• Present age of Rajan is 27 years.

Given :-

• The age of Rajan is 9 times that of his son. After 3 years, age of Rajan would be 5 times of his son.

To Find :-

• Their present ages.

Solution :-

• Let present age of Rajan's son be x

• Present age of Rajan will be 9x

After 3 years

• Rajan's son's age = x + 3

• Rajan's age = 9x + 3

Rajan would be 5 times of his son

According to question :-

• 5 (x + 3) = 9x + 3

➪ 5x + 15 = 9x + 3

➪ 15 - 3 = 9x - 5x

➪ 12 = 4x

➪ x = 12/4

➪ x = 3

✫ Present age of Rajan's son is 3 years

✫ Present age of Rajan is 9x = 27 years

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