Math, asked by plabade3601, 6 months ago

The age of remya and double the age of sofi gives 28.three fourth of remyas age added to one fourth of sofis age gives 11.what is the age of remya and sofi

Answers

Answered by sanskrutigore0724
0

Answer:

Let the present age of nisha be x

Asha's age is 2 more than square of Nisha's age i.e.,x

2

+2

In second situation age of Nisha is x

2

+2

Age of asha is one less than 10 times the present age of Nisha

i.e.,10x−1

In both the situations the age gap between them will be same

So x

2

+2−x=10x−1−x

2

−2

2x

2

−11x+5=0

2x

2

−10x−x+5=0

2x(x−5)−1(x−5)=0

(2x−1)(x−5)=0

x=5,

2

1

So the present age of Nisha is 5 and present age of Asha is

(5)

2

+2=27

Answered by BrainlyVanquisher
1

Answer:—

The age of Remya = 12 years

And the age of Sofi = 8 years

Step-by-step explanation:—

Let the age of Remya be R years.

And age of Sofi be S years.

★ Given that:-

Age of Remya and double the age of Sofi added together gives 28.

→ R + 2S = 28

→ R = 28 - 2S ________(i)

★ Solution:-

Three fourth of Remya's age added to one fourth of Sofi's age gives 11.

→ 3R/4 + S/4 = 11

→ (3R + S)/4 = 11

→ 3R + S = 11 × 4

→ 3R + S = 44

★ Substituting ;value of R from equation (i):

→ 3(28 - 2S) + S = 44

→ 84 - 6S + S = 44

→ 6S - S = 84 - 44

→ 5S = 40

→ S = 40/5

→ S = 8

∴ Sofi's age = S = 8 years

★ Substituting the value of S in equation (i):

→ R = 28 - (2 × 8)

→ R = 28 - 16

→ R = 12

∴ Remya's age = R = 12 years

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