Question

the age of Rohit and mohit are in the ratio of 12:7 six years later their age will be in the ratio of 3:2 find present age

Answer 1

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$\underline{SOLUTION}$ ➡

$Given ,\\ \\ Ratio \: of \: present \: age \: of \: Rohit \:\\ and \: Mohit= 12 : 7 \\ \\ Let ,\\ \\ \\ Present \: age \: of \: Rohit \: = 12x \: \: years\\ \\ Present \: age \: of \: Mohit \: = 7x \: \: years$

$After \: \: 6 \: years, \: \\ \\ Rohit\: age\: will \: be \: =( 12x + 6) \: years \\ \\ Mohit\: age\: will \: be \: =( 7x + 6) \: years$

$Given, \\ \\ After \: 6 \: years \: ratio \: of \: Rohit \: \\ and \: Mohit \: ages \: will \: be \: = 3 : 2$

$A.T.Q., \\ \\ (12x + 6) : (7x + 6) = 3 : 2 \\ \\ = > \frac{12x + 6}{7x + 6} = \frac{3}{2} \\ \\ = > 2(12x + 6) = 3(7x + 6) \\ \\ = > 24x + 12 = 21x + 18 \\ \\ = > 24x - 21x = 18 - 12 \\ \\ = > 3x = 6 \\ \\ = > x = \frac{6}{3} \\ \\ = > x = 2$

$So ,\\ \\ Present \: age \: of \: Rohit \: = 12x \: \: \: years \\ \\ = (12 \times 2) \: years \\ \\ = 24 \: \: years \\ \\ \\ Present \: age \: of \: mohit \: = 7x \: \: \: years \\ \\ =( 7 \times 2) \: years \\ \\ = 14 \: \: years$

$\underline{ANSWER}$ ➡

$Present \: age \: of \: Rohit \: = 24 \: \: years \\ \\ Present \: age \: of \: Mohit \: = 14 \: \: years$

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