Question

The age of Shaurya and Kauravki is in the ratio 2:6. After 5 years, the ratio of their ages will become 6:8. Find the average of their ages after 10 years

Answer 1

Answer:

12

Step-by-step explanation:

Let the age of Shaurya be s and the age of Kauravki be k.

Then,

s/k = 2/6 = 1/3

3s = k

(s + 5)/(k + 5) = 6/8 = 3/4

4(s + 5) = 3(k + 5)

4s + 20 = 3k + 15

4s - 3k + 5 = 0

Substituting k = 3s,

4s - 3(3s) + 5 = 0

5s = 5

s = 1

k = 3

After 10 years,

s = 10 + 1 = 11

k = 10 + 3 = 13

Average of s and k:

(11 + 13)/2 = 12

Answer 2

let be the X

the age of shaurya be 2x and kauravki age of 6x

after 5 years

2x+5/ 6x+5=6/8

=12x+30=48x+40

12x-48x=40-30

36x=10

x=10/36

x=5/18 answer