Math, asked by guddy64, 1 year ago

The age of sony and her mother together is 72 .if the mother age is 3 times that of sony , find their present ages.​

Answers

Answered by Gurkha
22

Answer:

Sony's age=18           Mother's age=54

Step-by-step explanation:Let sony's age=x

                                            Let mother's age=3x 3 times more than sony)

Now,

Sony's age+Mother's age=72

or, x+3x=72

or,4x=72

or,x=72/4

   x=18 years

Sony's age=x=18

Mother's age=3x=3*18=54 years

Answered by aditya111175
10

Answer:

Sony 's age is 18 and her mother age is 54

Step-by-step explanation:

Let x and y be the present ages of Sony and his mother respectively.

According to question x+y=72.......(1)

Again Sony's mother age is three times that of Sony age i,e y=3x.............(2)

Put the value of y of equation 2 in eq. 1, we get x+3x=72

or 4x=72

or x=72/4=18

As we have already taken x is the Sony's age so her mother age is three times of Sony's age i,e 3×18=54 age

Therefore the present age of Sony and her mother ages are 18 and 54 respectively.

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