Question

The age of Supriya and Neetu are in the ratio 5:6 . After two years, their age will be in the ratio 6:7 . What are their present ages?​

Answer 1

Answer:

let the common multiple be x.

therefore their ages are 5x and 6x.

thus according to the question,

5x+2/6x+2=6/7

after cross multiplication,

35x+14=36x+12

-x=-2

therefore x=2.

thus their ages are 5x2=10 yrs(supriya)

and 6×2=12 yrs(neetu).

Answer 2

Step-by-step explanation:

Let present age of supriya be x yrs and Neetu be y

As condition 1,

5/6=x/y

As condition 2

After 2 years = x + 2

= y + 2

6/7 =x +2 / y + 2

5y = 6x

6x - 5y =0 .....(1)

6(y + 2) = 7(x + 2)

6y + 12 = 7x +14

7x - 6y =-14 + 12

7x - 6y = -2 ......(2)

multiplying equ (1) with 6 and (2) with 5

36x - 30y = 0 ......(3)

sub 35x - 30y = -10 .....(4)

x = 10

putting x=10 in equ (1)

6×10 - 5y = 0

60 -5y =0

-5y =0-60

-5y = -60

y=-60/-5

y=8

The age of supriya is 10 yrs

Neetu age is 8 yrs