Question

the age of the father 3 years ago was 7 times of the age of his son at present the age is five times that of his son what are the present age of the son and father​

Answer 1

Step-by-step explanation:

HEYA UR ANSWER IS:

Let present of son is be x,

Age of son 3 years ago = x-3

Age of father 3 years ago = 7(x-3)

Present age of son = x

Present age of father = 5x

=>7(x-3) = 5x - 3

=>7x-21 = 5x - 3

=>7x-5x = 21 - 3

=>2x = 18

=>x = 18/2 = 9

Therefore, present age of father = 5x = 5*9 = 45

present age of son = x = 9

HOPE IT HELPS YOU!!!

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Answer 2

Answer:

Let the present age son be x years and present age of father be 5x years.

❏ According to Question now,

➳ 7(x - 3) = 5x - 3

➳ 7x - 21 = 5x - 3

➳ 7x - 5x = -3 + 21

➳ 2x = 18

➳ x = 18/2

➳ x = 9 years

⬤ Therefore,

• Present age of son = x = 9 years

• Present age of father = 5x = 45 years.