Math, asked by Dibyanshu691, 10 months ago

The age of the father 4 years ago was 8 times the age of his son. At

present, the father's age is 4 times that of his son. Find the present age of

son.

A) 9 years B) 7 years
C) 14 years D) 18 years​

Answers

Answered by nichumhr248887
2

Answer:

A) 7 years

let the age of the son be x

present age of father=4x years

according to the question, 4 years ago,

8(x-4)= 4x-4

8x-32 = 4x-4

8x-4x-32+4=0

4x-28=0

x=28/4

x=7 years

hope it helps.

all the best! =)

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