The age of the father 4 years ago was 8 times the age of his son. At
present, the father's age is 4 times that of his son. Find the present age of
son.
A) 9 years B) 7 years
C) 14 years D) 18 years
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Answer:
A) 7 years
let the age of the son be x
present age of father=4x years
according to the question, 4 years ago,
8(x-4)= 4x-4
8x-32 = 4x-4
8x-4x-32+4=0
4x-28=0
x=28/4
x=7 years
hope it helps.
all the best! =)
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