Math, asked by pappulakoushik5265, 9 months ago

The age of the father 8 years ago was 5 times the age of his son. At present the father's age is 3 times that of his son. Find the present age of father.

Answers

Answered by Mahendranadh
0

Answer:

father=63

SON=21

Step-by-step explanation:

father=x

son=y

8 years ago

fathrrs age= x-8

son age=y-8

The age of the father 8 years ago was 5 times the age of his son.

x-8=5(y-8)

x-8=5y-40

-8+40=5y-x

5y-x=42

At present the father's age is 3 times that of his son.

x=3y

x-3y=0

x-3y=0

(+)-x+5y=42

_______________

2y=42

y= 42/2

y=21

x=3y

x=3×21

x=63

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