Question

The age of the father exceeds twice that of his son by 10 years. Twenty years ago, the age of the father was five times that of his son. Find their present ages.

Answer 1

helloowww the future one of the present !
Let the present age of the son be 'x'.
Then, the age of the father = 2x+10
Before 20 yrs,
age of the father = 5×( age of the son )
(2x+10-20) = 5×(x-20)
or, 2x-10 = (5x - 100)
or, 2x-5x = -100 + 10
or, -3x = -90
or, x = -90/-3
or, x = 30
i.e. age of son = 30yrs
and age of father = 2x + 10 = 2×30 + 10 = 60 + 10 = 70yrs

Hope you are satisfied!

Answer 2

Solution for this question